WebTo return the expected result set in Crystal Reports, you can either: Convert NULL values to default; or; Add the function isNull in the formula Convert NULL values to default; In Crystal Reports, open the report. Under the menu "File", select "Report Options..." Check the option "Convert Database NULL Values to Default" Click "OK" Save the report. WebJun 3, 2013 · InStr() returns the starting character position of the desired string, and therefore is greater than zero when the string exists within the other and thus why the …
Crystal Reports Contains * in text string formula
WebI have been trying to write a function to check if a string contains a number without that number being part of a bigger number (in other words if the number being searched for is … WebApr 11, 2012 · How to check if a string field contains a character in crystal reports formula. You can use Instr ( {text.field},'-') > 0 - indicates there is a character in the string field.. if Instr ( {text.field},'-') = 0 - indicates there are no such characters in the string field. Posted by Realtimeexp at 9:32 AM. phoebe cake stand
Crystal Reports Finding if a value is in an array
WebFeb 16, 2016 · There may be a way to program Crystal Reports to do it; let me know if you know how!" 6. Open the Select Expert. Click Report --> Select Expert... 7. Within the Select Expert, Pull down the first pick list and click "is equal to". Pull down the second pick list and click on the Parameter Field you just created. WebTo use a formula in report: Create a new formula. Open the Field Explorer (Crystal XI: View > Field Explorer; Crystal 8.5: Insert > Field Object) Right-click on Formula Fields. Select New. Enter a name for the formula. Click OK. Use … WebJun 19, 2007 · You may need to break your arrays down into smaller chuncks. Another technique would be to add a table containing the postal codes to your database, then add it to the report with a left outer join from the postal code in your data to this new table. You could then test to see if the value from the new table is null to determine whether or not ... tsyndicate virus